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585=11x-0.05x^2
We move all terms to the left:
585-(11x-0.05x^2)=0
We get rid of parentheses
0.05x^2-11x+585=0
a = 0.05; b = -11; c = +585;
Δ = b2-4ac
Δ = -112-4·0.05·585
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-2}{2*0.05}=\frac{9}{0.1} =90 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+2}{2*0.05}=\frac{13}{0.1} =130 $
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